t^2-(64/121)=0

Solution for t^2-(64/121)=0 equation:

t^2-(64/121)=0

We add all the numbers together, and all the variables

t^2-(+64/121)=0

We get rid of parentheses

t^2-64/121=0

We multiply all the terms by the denominator


t^2*121-64=0

Wy multiply elements

121t^2-64=0

a = 121; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·121·(-64)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-176}{2*121}=\frac{-176}{242}
=-8/11
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+176}{2*121}=\frac{176}{242}
=8/11
$